Tiber Tutor

notes

IB Maths AA 5.5 Notes

This page contains our IB Maths AA notes for 5.5. By reading each one of these notes, you will fully cover the content for IB Maths AA 'Advanced integration'.

Chapters

Loading progress...

Indefinite integrals

Integration extends beyond simple polynomials. In this section, you work with indefinite integrals of xnx^n, sin⁡x\sin x, cos⁡x\cos x, 1x\frac{1}{x} and exe^x, together with linear composites such as f(ax+b)f(ax+b), and integrals that can be solved by inspection or substitution.

An indefinite integral gives a family of antiderivatives, so every answer must include a constant of integration CC.

∫xn dx=xn+1n+1+C\int x^n\,dx=\frac{x^{n+1}}{n+1}+C

  • ∫xn dx=xn+1n+1+C\int x^n\,dx=\frac{x^{n+1}}{n+1}+C, where n∈Qn\in\mathbb{Q} and n≠−1n\ne-1
  • ∫sin⁡x dx=−cos⁡x+C\int \sin x\,dx=-\cos x+C
  • ∫cos⁡x dx=sin⁡x+C\int \cos x\,dx=\sin x+C
  • ∫ex dx=ex+C\int e^x\,dx=e^x+C
  • ∫1x dx=ln⁡∣x∣+C\int \frac{1}{x}\,dx=\ln|x|+C

The logarithm result is specifically required in the form ln⁡∣x∣+C\ln|x|+C.

Some examples include:

  • ∫6x4 dx=6∫x4 dx=6(x55)+C=65x5+C\int 6x^4\,dx=6\int x^4\,dx=6\left(\frac{x^5}{5}\right)+C=\frac{6}{5}x^5+C
  • ∫2x−53 dx=2(x−23−23)+C=−3x−23+C\int 2x^{-\frac{5}{3}}\,dx=2\left(\frac{x^{-\frac{2}{3}}}{-\frac{2}{3}}\right)+C=-3x^{-\frac{2}{3}}+C
  • ∫(x4+2x−53) dx=x55−3x−23+C\int \left(x^4+2x^{-\frac{5}{3}}\right)\,dx=\frac{x^5}{5}-3x^{-\frac{2}{3}}+C

tibertutor.com

Next Up

You have completed the sub-topic 5.5 notes, covering "Advanced integration" for IB Maths AA - continue with related resources below or explore the full IB Maths AA course from the IBO.

Other Sub-topic 5.5 resources